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Ψηφοφορία θέματος φόρουμ
5 + 5 + 5 - 5 + 5 + 5 - 5 + 5 x 0 = ?
Συνδεθείτε για να ψηφίσετε ή να δείτε τα αποτελέσματα της ψηφοφορίας
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Θέμα: 5 + 5 + 5 - 5 + 5 + 5 - 5 + 5 x 0 = ? |
353 απαντήσεις
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Quote ( Shoaib Mohamed @ April 5th 2012,20:04:42 )
Dick shaped
With your profile picture, I don't want to imagine what you think of.
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Quote ( Phil Maunder @ April 5th 2012,19:36:34 )
1 = 2
Yes 1 =2
X = Y
so
X-Y=0
Both sides times 2 ;)
2X-2Y=0
Lets say then
2X-2Y = X - Y , true because both sides are still 0 :)
So
2(X-Y) = X - Y
Now divide both sides by X-y!
2=1!!!!!!!!
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Quote ( Andrew Lawrence @ April 5th 2012,20:08:33 )
With your profile picture, I don't want to imagine what you think of.
With your posts, I don't want to imagine what you think of.
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ORDER OF CALCULATIONS:
1-Brakets
2-Exponential
3-MULTIPLICATION AND DIVISION
4-ADDITION AND SUBSTRACTION
Try =5+5+5-5+5+5-5+5*0 in Excel, then those that say it`s 0, SHUT UP and listen in school!!!
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My friend is asking (yeah....many people is reading this thread yet :D ).....
-infinity + (+infinity) :2 = ?
BUT TAKE A NOTE>>>TODAY IS GREEN THURSDAY LOL :D :D
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Quote ( Eric Bolder @ April 5th 2012,20:21:46 )
Yes 1 =2
X = Y
so
X-Y=0
Both sides times 2 ;)
2X-2Y=0
Lets say then
2X-2Y = X - Y , true because both sides are still 0 :)
So
2(X-Y) = X - Y
Now divide both sides by X-y!
2=1!!!!!!!!
This has been explained various times. You cannot divide by X-Y because it equals 0. You cannot divide by 0
Quote ( Daneks Britāls @ April 5th 2012,20:38:28 )
-infinity + (+infinity) :2 = ?
This isnt a valid question. You cant use infinity as a real number ... mainly because it is not.
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Quote ( Marcelo Michelini @ April 5th 2012,20:02:50 )
Quote ( Phil Maunder @ April 5th 2012,19:36:34 )
pps. it's also possible to prove that 1 = 2
that's not possible
Let me prove to you: 4 = 5
-20 = -20
16 - 36 = 25 - 45
4^2 - 9*4 = 5^2 - 9*5
4^2 - 9*4 + 81/4 = 5^2 - 9*5 + 81/4
(4 - 9/2)^2 = (5 - 9/2)^2
4 - 9/2 = 5 - 9/2
4 = 5
Go.
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Well, clearly you cheated applying that square root there and ignoring the fact that square root[(4 - 9/2)^2] can be both -0.5 and +0.5, after you actually calculate this (4 - 9/2)^2 to be 0.25. :)
So, technically, what you did above is incorrect.
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Hush Andrei. I wanted to see how much time passed before people figured that out :p
I should have probably elaborated it a bit more and put some more functions in there after that step...
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Quote ( Chinmay Dhopate @ April 8th 2012,23:49:32 )
-20 = -20
16 - 36 = 25 - 45
4^2 - 9*4 = 5^2 - 9*5
4^2 - 9*4 + 81/4 = 5^2 - 9*5 + 81/4
(4 - 9/2)^2 = (5 - 9/2)^2
4 - 9/2 = 5 - 9/2
4 = 5
Line 1 - correct
Line 2 - correct
Line 3 - correct
Line 4 - correct
Line 5 - correct
Line 6 - incorrect. Square roots of numbers are not unique over R. Therefore you cannot say because two numbers squared give the same answer, those numbers must be the same - it's an incorrect statement.
Next?
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Quote ( Chinmay Dhopate @ April 8th 2012,23:49:32 )
4^2 - 9*4 = 5^2 - 9*5
This is incorrect because:
4^2 = 16
16 - 9 = 7
7*4 = 28
and
5^2 = 25
25-9 = 16
16*5 = 80
... or so half the ppl in this thread would say...
/sarcasm
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probably :D because "there are no brackets ! " :)
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It's zero because if x0 at the end of a sum your answer is always zero
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Quote ( James Hitchen @ September 29th 2012,20:37:28 ) It's zero because if x0 at the end of a sum your answer is always zero
Go back to school ! :P
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Wow... BIDMAS/BODMAS rule, however you like to say it. Read up on that basic maths rule, James.
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Quote ( James Hitchen @ September 29th 2012,20:37:28 ) It's zero because if x0 at the end of a sum your answer is always zero
No parentheses!! So 15!
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